Asked by naomi

A particle is projected with a speed of 39.2m/sec at an elevation of 30degrees.find its greatest height.

Answers

Answered by Steve
at max height, v=0

sin 30 = 1/2, so the velocity is given by

39.2/2 - 9.8t = 0
t = 4

So, it rose for 4 seconds to max height.

Now recall that the height is given by

h = 39.2t - 4.9t^2

Just plug in t=4
Answered by Star
How did you get 9.8t pls
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