Asked by Anonymous
Searches related to a stone is projected vertically upward with a speed of 14m/s from a tower 100m high. find the maximum height attained and the speed with which it strikes the ground
Answers
Answered by
Damon
How high does it go?
v = Vi -9.81 t
at top v = 0
0 = 14 -9.81 t
so
t = 14/9.81
then
h = 100 + 14 t - 4.9 t^2
now fall from h
v^2 = 2 g h
v = Vi -9.81 t
at top v = 0
0 = 14 -9.81 t
so
t = 14/9.81
then
h = 100 + 14 t - 4.9 t^2
now fall from h
v^2 = 2 g h
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