Question

Searches Related to 1. A mass of 20 kg is suspended at the end of a rubber cord of diameter 2.0 mm and length 100 cm. Find the period of vertical oscillations of the mass. [Take young’s modulus E, for the rubber = 2.0 x 108 Nm - 2

Answer 1

r = .001 meter

Area = pi r^2 = 3.14 * 10^-6 m^2

delta L/L = F /( E A )

delta L/1 m = F /(2*10*8 *3.14*10^-6)

F/delta L = spring constant = k 628 N/m

now I am sure you can do the sqrt (k/m) thing

Answer 2

I donot understand a thing..