Two hiking paths diverge at an angle of 75°. If one person took a path and walked 5 km/h and another person took the other path and walked at 6 km/h, how far apart are they after 1½ hours?

Answer 1

Draw a triangle with your one angle as 75 degrees and the two adjacent sides as how far each person walked after 1.5 hrs. Then law of cosines

c^2=7.5^2+9^2- 2(9)(7.5)cos75
solve for c

Answer 2

use law of cosines. Your distance z can be found by
z/1.5 = 5^2 + 6^2 - 2*5*6 cos75°

Answer 3

D1 = V1 * t = 5km/h[75o] * 1.5h = 7.5 km[75o].

D2 = V2 * t = 6km/h[0o] * 1.5h = 9 km[0o].

D = D2 - D1 = 9[0o] - 7.5[75o] = 9 - 1.94 - 7.24i = 7.06 - 7.24i.
D = sqrt(X^2+Y^2) = sqrt(7.06^2+7.24^2) =