A person walks the path shown below. The total trip consists of four straight-line paths.

Path 1 is 100.0 m due east.
Path 2 is 270.0 m due south.
Path 3 is 140.0 m 30.0° south of west.
Path 4 is 160.0 m 60.0° north of west.
At the end of the walk, what is the person's resultant displacement?
m at ° south of west.

2 answers

get out some graph paper and draw the line segments.
Or, calculate the x- and y-distances for each part and add them up.
If you end up at (x,y), then tanθ = |y/x|
203.11 m