they both go distance d
first one travels time = t+3
second one travels time = (t)
d = 6 (t+3) = 10(t)
6 t + 18 = 10 t
4 t = 18
t = 9/2 = 4.5 hr
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
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