how do u come up w/the answer?
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
2 answers
Math assistance needed.
The distance they travel is the same...
dfirst=6*time
dsecond=10*(time-3)
set the two equations equal, solve for time.
dfirst=6*time
dsecond=10*(time-3)
set the two equations equal, solve for time.
2 answers