To solve this problem, we can use the formula:
Time = Distance / Speed
Let's assume that the time passed when the second cyclist catches up with the first cyclist is represented by "t" (in hours).
By the time the second cyclist starts biking, the first cyclist has already been biking for 3 hours. Therefore, the first cyclist has already covered a distance of:
Distance1 = Speed1 * Time1
= 6 * 3
= 18 miles
Now, we need to find the time it takes for the second cyclist to cover the same distance as the first cyclist.
Distance2 = Speed2 * Time2
Distance2 = 10 * t
We know that Distance1 = Distance2, so we can equate the two equations:
18 = 10 * t
To solve for t, we can divide both sides by 10:
t = 18 / 10
t = 1.8 hours
Therefore, it will take approximately 1.8 hours (or 1 hour and 48 minutes) for the second cyclist to catch up with the first cyclist from the time when the second cyclist started biking.