Asked by test comin up
how do u come up w/the answer?
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
Answers
Answered by
Writeacher
Math assistance needed.
Answered by
bobpursley
The distance they travel is the same...
dfirst=6*time
dsecond=10*(time-3)
set the two equations equal, solve for time.
dfirst=6*time
dsecond=10*(time-3)
set the two equations equal, solve for time.
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