Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist eho is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?

Question

Two cyclists start biking from a trail's start 3 hours apart.  The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist eho is traveling at 6 miles per hour.  How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?

drwls · Answer

The faster cyclist "closes the gap" at a rate of 10 - 6 = 4 miles/hour. The initial lead of the slower cyclist is 3*6 = 18 miles. Divide 18 miles by 4 miles/hour for the answer in hours

Anonymous · Answer

5566