When the cells are connected in parallel, the voltage remains the same, so the total voltage across the 4 ohm resistance is still 1.5V.
The total internal resistance of the two cells connected in parallel is equal to the reciprocal of the sum of the reciprocals of the individual internal resistances:
1/R_total = 1/2 + 1/2
R_total = 1 ohm
The total resistance in the circuit is then the sum of the 4 ohm resistance and the total internal resistance:
R_total_circuit = 4 + 1 = 5 ohms
Using Ohm's Law, the current can be calculated as:
I = V / R
I = 1.5V / 5 ohms
I = 0.3A
Therefore, the current in the 4 ohm resistance when the two cells are connected in parallel is 0.3A.
two cells each having a voltage of 1.5v and an internal resistance of two ohms are connected to a resistance of 4 ohms. what is the current in this resistance if the cells are connected in parallel?
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