Three cells are connected as shown. The internal resistance of each cell is 2 ohms. The voltage of each cell is 1.5 volts. The resistance of the external circuit is 2.3 ohms. What is the circuit current to the nearest tenth ampere?

Answer 1

To find the circuit current, we can use Ohm's Law, which states that the current flowing through a circuit is equal to the voltage divided by the resistance.

First, we need to find the total internal resistance of the three cells. Since each cell has an internal resistance of 2 ohms, the total internal resistance is 2 ohms + 2 ohms + 2 ohms = 6 ohms.

Next, we can find the total resistance of the circuit by adding the external resistance to the total internal resistance. Therefore, the total resistance is 6 ohms + 2.3 ohms = 8.3 ohms.

Now, we can use Ohm's Law to find the circuit current. The voltage provided by the three cells is 1.5 volts each, so the total voltage provided is 1.5 volts + 1.5 volts + 1.5 volts = 4.5 volts.

Therefore, the circuit current is 4.5 volts / 8.3 ohms = 0.5 amperes.

So, the circuit current is approximately 0.5 amperes to the nearest tenth.