Three different size lights are running off a low voltage system. The resistance of the three lights are R1 =3 ohms, R2 = 9 ohms, and R3 = 9 ohms. They are all connected in parallel with a 5.0 V battery. The internal resistance of the battery is negligible.

What is the current through R1?

3 answers

I=R/V
1.67A? Right?
correct. The entire 5V drop happens for each bulb, since they are in parallel.
I = E/R = 5/3___Amps.