Two cars, A and B, travel in a straight line. The distance of A from the starting point is given as a function of time by xA(t)=αt+βt^2, with α=2.60m/s and β=1.20m/s^2. The distance of B from the starting point is xB(t)=γt^2−δt^3, with γ=2.80m/s^2 and δ=0.20m/s^3.

Question

Which car is ahead just after they leave the starting point?

At what time(s) are the cars at the same point?

First time taking physics, appreciate any help!

Answer 1

at the starting point, t is very small. If A is ahead, then A-B must be negative.
A-B=αt+βt^2-γt^2+δt^3. For very small t, the first term will predominate. A is ahead.

When is A-B=0?
2.6t+1.2t^2-2.8t^2+.2t^3=0
combine the t^2 terms.
then factor out a t, you are left with a quadrataic equation, solve it.

Answer 2

5.7320

Answer 3

Give me ansuwer

Answer 4

answer me