the formula for y (distance) is bogus
m/s^3 * t^2 = m/s
the units don't work out right.
It could be that you meant
x = 4t + t^2
y = 2t + 2t^2
If so, then
(a) set x=y and solve for t
(b) set the speeds equal and solve for t
Two cars,a and b travel in a straight line.The distance of a from the starting point is given by x=(4m/s)t+(1m\s^2)t^2;the distance of b from starting point is y=(2m/s^2)t^2+(2m/s^3)t^2;
(a)At what times are the cars at the same point?
(b)At what times is the velocity of b relative to a zero?
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