To determine the force exerted by the 7 kg bowling ball on the 4 kg bowling ball, we can use Newton's second law, which states that \( F = m \cdot a \), where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration.
Since both balls are accelerating at \( 1.875 , \text{m/s}^2 \), we can calculate the force exerted by each ball.
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Force exerted by the 7 kg bowling ball: \[ F_{7kg} = m \cdot a = 7 , \text{kg} \cdot 1.875 , \text{m/s}^2 = 13.125 , \text{N} \] This force is exerted to the right (since this ball is rolling to the right).
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Force exerted by the 4 kg bowling ball: \[ F_{4kg} = 4 , \text{kg} \cdot 1.875 , \text{m/s}^2 = 7.5 , \text{N} \] This force is exerted to the left (since this ball is rolling to the left).
According to Newton's third law, the force that the 7 kg ball exerts on the 4 kg ball is equal in magnitude and opposite in direction to the force that the 4 kg ball exerts on the 7 kg ball.
Since we are asked specifically for the force that the 7 kg bowling ball exerts on the 4 kg bowling ball, it can be stated as 7.5 N to the left.
Therefore, the answer to your question is 7.5 N to the left.
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