Two bowling balls of different masses collide while accelerating at 1.875 m/s 22 . The first ball, rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?(1 point) Responses 3.73 N to the right 3.73 N to the right 7.5 N to the left 7.5 N to the left 13.125 N to the right 13.125 N to the right 8.875 N to the right 8.875 N to the right

1 answer

To find the force that the 7 kg bowling ball exerts on the 4 kg bowling ball, we can use Newton's second law, which states that Force (F) is equal to mass (m) multiplied by acceleration (a):

\[ F = m \cdot a \]

The problem states that both bowling balls are accelerating at \( 1.875 , \text{m/s}^2 \).

  1. Calculate the force exerted by the 7 kg ball (to the right):
    \[ F_1 = m_1 \cdot a = 7 , \text{kg} \cdot 1.875 , \text{m/s}^2 = 13.125 , \text{N} \]

  2. Direction of the force: Since the 7 kg ball is rolling to the right, it exerts this force to the right.

According to Newton's third law, the forces are equal in magnitude and opposite in direction. So, the 7 kg bowling ball exerts a force of \( 13.125 , \text{N} \) to the right on the 4 kg bowling ball.

To answer the question, the force that the 7 kg bowling ball exerts on the 4 kg bowling ball is:

13.125 N to the right.

So, the correct response is 13.125 N to the right.