Two bowling balls of different masses collide while accelerating at 1.875 m/s 2

Question

2
. The first ball, rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?(1 point)
Responses

13.125 N to the right
13.125 N to the right

7.5 N to the left
7.5 N to the left

8.875 N to the right
8.875 N to the right

3.73 N to the right

Answer 1

To find the force that the 7 kg bowling ball exerts on the 4 kg bowling ball during their collision while they are accelerating, we can use Newton's second law, \( F = ma \).

1. Calculate the force exerted by the 7 kg bowling ball:

   • Mass (m) = 7 kg
   • Acceleration (a) = 1.875 m/s²

   Using the formula: \[ F = ma = 7\ \text{kg} \times 1.875\ \text{m/s}^2 = 13.125\ \text{N} \]

The direction of the force is the same as the direction of the acceleration of the 7 kg ball, which is to the right.

So, the force that the 7 kg ball exerts on the 4 kg ball is 13.125 N to the right.

Therefore, the correct answer is:

13.125 N to the right.