Two bowling balls of different masses collide while accelerating at 1.875 m/s 2

Question

. The first ball, rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?(1 point)
Responses

3.73 N to the right
3.73 N to the right

7.5 N to the left
7.5 N to the left

13.125 N to the right
13.125 N to the right

8.875 N to the right

Answer 1

To determine the force that the bowling ball weighing 7 kg exerts on the bowling ball weighing 4 kg, we can use Newton's second law of motion, which tells us that \( F = m \cdot a \).

Given:

• The mass of the first ball (m₁) = 7 kg
• The mass of the second ball (m₂) = 4 kg
• The acceleration (a) = 1.875 m/s²

Step 1: Calculate the Force exerted by the first ball (7 kg)

Using the formula \( F = m \cdot a \):

\[ F_1 = m₁ \cdot a \] \[ F_1 = 7 , \text{kg} \cdot 1.875 , \text{m/s}² \] \[ F_1 = 13.125 , \text{N} \]

Step 2: Direction of the Force

Since the first ball is rolling to the right, the force it exerts on the second ball (the ball weighing 4 kg) will also be to the right.

Conclusion:

The force that the bowling ball weighing 7 kg exerts on the bowling ball weighing 4 kg is 13.125 N to the right.

So the correct answer is: 13.125 N to the right.