To calculate the force that the 7 kg bowling ball exerts on the 4 kg bowling ball while both are accelerating at 1.875 m/s², we can use Newton's second law of motion:
\[ F = m \cdot a \]
where \( F \) is force, \( m \) is mass, and \( a \) is acceleration.
- For the 7 kg bowling ball:
\[ F_1 = m_1 \cdot a = 7 , \text{kg} \cdot 1.875 , \text{m/s}^2 = 13.125 , \text{N} \]
This force is directed to the right (in the direction of its acceleration).
- For the 4 kg bowling ball:
\[ F_2 = m_2 \cdot a = 4 , \text{kg} \cdot 1.875 , \text{m/s}^2 = 7.5 , \text{N} \]
This force is directed to the left since the ball is rolling to the left.
According to Newton's third law of motion, the force that the 7 kg ball exerts on the 4 kg ball is equal in magnitude and opposite in direction to the force that the 4 kg ball exerts on the 7 kg ball. Therefore, the force exerted by the 7 kg ball on the 4 kg ball will also be 13.125 N, but directed to the left.
Thus, the answer to the question of what force the 7 kg ball exerts on the 4 kg ball is:
13.125 N to the left.
However, since this option isn't available, let's clarify the options:
- 13.125 N to the right (incorrect)
- 7.5 N to the left (force exerted on the 7 kg by the 4 kg)
- 3.73 N to the right (incorrect)
- 8.875 N to the right (incorrect)
If we’re only considering the direct answer, it's 13.125 N to the left as mentioned before. The closest correct answer about the force exerted by the 7 kg ball on the 4 kg ball was incorrectly stated, but the force exerted from the heavier ball towards the lighter ball is not reflected correctly in the options given. Would you like assistance with another question?
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