Two boats A and B left port C at the same time on different routes B traveled on a bearing of 150° and A traveled on the north side of B.when A had traveled 8km and B had traveled 10km. The distance between the two boats was found to be 12km.calculate the bearing of A's route from C.

Answer 1

You travel on a heading, not a bearing. Math texts drive me crazy.
triangle ABC has sides 8, 10,12
lets find angle ACB
12^2 = 10^2 + 8^2 - 2 * 10 *8 cos C
160 cos C = -144 + 100+ 64 = 20
cos C = 20/160 = .125
C = 82.8 degrees
so
Angle of AC clockwise from north = 150 - 82.8 = 67.2 degrees about East North East