two boats a and b left a port at the same time on different routes. b travelled on a bearing of 150 and a travelled on north side of b. when a had travelled 8km and b had travelled 10km, the distance between the two boats was found to be 12km calculate the bearing of a route from c
3 answers
i have not seen the solution to my question
Patience, child!! We are human beings who volunteer to help students. We are not here 24/7. A math tutor will try to help you when s/he is online.
geez - impatient much?
Draw it, and if you call the starting point O, then you have a triangle OAB with a=10, b=8. So, you can find angle O = θ using the law of cosines:
8^2 + 10^2 - 2*8*10*cosθ = 12^2
cosθ = 1/8
θ = 82.8°
So you know that the bearing of A from O is 150-82.8 = 67.2°
Now just do the usual calculations to find the actual locations of A and B, relative to O.
Maybe by then you will know what the heck "c" is.
Draw it, and if you call the starting point O, then you have a triangle OAB with a=10, b=8. So, you can find angle O = θ using the law of cosines:
8^2 + 10^2 - 2*8*10*cosθ = 12^2
cosθ = 1/8
θ = 82.8°
So you know that the bearing of A from O is 150-82.8 = 67.2°
Now just do the usual calculations to find the actual locations of A and B, relative to O.
Maybe by then you will know what the heck "c" is.