A, 650 * 1.5 = 975
B, 560 * 1.5 = 840
angle between them = 108 - 40 = 68
draw parallelogram bottom 975, left 840, top 975, right 840, angle 68 at bottom left
c^2 = 840^2 + 975^2 - 840*975 cos 68
= 705600 + 950625 - 819000 *.3746
= 349,427
so diagonal c = 1,161
Two airplanes leave an airport at the same
time. The velocity of the first airplane is
650 m/h at a heading of 40◦
. The velocity of
the second is 560 m/h at a heading of 108◦
.
How far apart are they after 1.5 h?
Answer in units of m.
1 answer
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