All angles are measured CW from +y-axis.
d1 = 690[67.5o] * 3.5 = 2415m[67.5].
d2 = 620[182o] * 3.5 = 2170m[182o].
D = d1 - d2 = 2415[67.5] - 2170[182].
X = 2415*sin67.5 - 2170*sin182 = 2231 m.
Y = 2415*Cos67.5 - 2170*Cos182 = 3093 m.
D = sqrt(X^2 + Y^2).
Two airplanes leave an airport at the same
time. The velocity of the first airplane is
690 m/h at a heading of 67.5
The velocity
of the second is 620 m/h at a heading of 182◦
How far apart are they after 3.5 h?
Answer in units of m.
1 answer
1 answer