d separation.
Ok,lets call the force between A and B F.
then the force on C is F/4 towards A plus F away or a net of 3/4 F away from A and B.
the force on B is F towards A, and F (from C) towards A, or a force of 2F towards A.
The force on A is F towards B, plus F/4 towards B due to C, or a total force of 5/4 F towards B.
check: forces to the right =0 (left will be negative.
Total= Fa+Fb+Fc
= 5/4 F -2F+3/4 F=f(5/4-8/4+3/4)=0
all this is based on the INVERSE square law.
ranking. B, A, C check that.
Tree point charges(A---B---C)have equal magnitudes and are located on the same line.?
The separation d btw A and B is the same as btw B and C. A is +, B/C are -. Consider the net electrostatic force that each charge experience due to the other two charges. Rank the net forces in descending order (greatest first) according to magnitude. A,B,C / B,C,A / A,C,B / C,A,B / B,A,C. I'll appreciate the answer with a very brief reasoning. Thanks!
2 answers
C,A,B