Asked by mela
An electric dipole is made of two charges of equal magnitudes and opposite signs. The
positive charge, q = 1.0μC, is located at the point (x, y, z) = (0.00cm, 1.0cm, 0.00cm), while
the negative charge is located at the point (x, y, z) = (0.00cm,−1.0cm, 0.00cm). How much
work will be done by an electric field ~E
= (3.0 × 106N/C)~i
to bring the dipole to its stable
equilibrium position?
positive charge, q = 1.0μC, is located at the point (x, y, z) = (0.00cm, 1.0cm, 0.00cm), while
the negative charge is located at the point (x, y, z) = (0.00cm,−1.0cm, 0.00cm). How much
work will be done by an electric field ~E
= (3.0 × 106N/C)~i
to bring the dipole to its stable
equilibrium position?
Answers
Answered by
IDK
I think its .06 J
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