x + x + 1 + x + 2 = 357
3x + 3 = 357
3x = 357 - 3
3x = 354
x = 118
Three consecutive integers have a sum of 357. Fid the integers algebraically.
I know the three numbers are 118, 119, and 120 but how do you write it in an algebraic expression ?
1 answer