2.find four consecutive odd integers such that the sum of the two largest integers subtract from twice the sum of the two smallest integers is 96

Answer 1

Let the four consecutive odd integers be: x, x+2, x+4, x+6

The sum of the two largest integers: (x+4) + (x+6) = 2x + 10
Twice the sum of the two smallest integers: 2(x + x+2) = 4x + 4

The equation formed is: (2x + 10) - (4x + 4) = 96
Solving the equation:
2x + 10 - 4x - 4 = 96
-2x + 6 = 96
-2x = 90
x = -45

Plugging x back in to find the four consecutive odd integers:
-45, -43, -41, -39

Therefore, the four consecutive odd integers are -45, -43, -41, and -39.