x = first number
x + 1 = second number
1 / x + 1 / ( x + 1 ) = 17 / 72
[ 1 * ( x + 1 ) + 1 * x ] / [ x * ( x + 1 ) ] = 17 / 72
[ ( x + 1 ) + x ] / [ x * x + x * 1 ) ] = 17 / 72
( 2 x + 1 ) / ( x ^ 2 + x ) = 17 / 72 Multiply both sides by 72
72 * ( 2 x + 1 ) / ( x ^ 2 + x ) = 17
( 72 * 2 x + 72 * 1 ) / ( x ^ 2 + x ) = 17
( 144 x + 72 ) / ( x ^ 2 + x ) = 17 Multiply both sides by x ^ 2 + x
144 x + 72 = 17 * ( x ^ 2 + x )
144 x + 72 = 17 * x ^ 2 + 17 * x
144 x + 72 = 17 x ^ 2 + 17 x Subtract 144 x to both sides
144 x + 72 - 144 x = 17 x ^ 2 + 17 x - 144 x
72 = 17 x ^ 2 - 127 x Subtract 72 to both sides
72 - 72 = 17 x ^ 2 - 127 x - 72
0 = 17 x ^ 2 - 127 x - 72
17 x ^ 2 - 127 x - 72 = 0
The solutions are:
x = - 9 / 17 and x = 8
- 9 / 17 isn't positive integers so x = 8
first number = 8
second number = 8 + 1 = 9
Proof:
1 / x + 1 / ( x + 1 ) =
1 / 8 + 1 / 9 =
( 1 * 9 + 1 * 8 ) / ( 8 * 9 ) =
( 9 + 8 ) / 72 = 17 / 72
2. The sum of the reciprocals of two consecutive positive integers is 17/72. Write an equation that can be used to find the two integers. What are the integers?
Steve helped me yesterday and gave me the hint 8+9=17. Then I thought about it and saw 8*9=72, but I am confused about how to put it into an equation.
3 answers
bruh why is that so long
cope