Three cards are drawn at random without replacement from a standard deck of 52 playing cards. What is the probability that the second and third cards are black?

Answer 1

There were 52 cards. Half were black
so
26/52 = .5
then we had 51 cards, 25 black
25/51
then we had 50 cards, 24 black
24/50
so
.5 * 25/51 * 24/50

Answer 2

Did not say that the first card could have been black also, so ..
26 Black , 26 Red

case 1, the first card was also black, that is, BBB
prob of that = (26/52)(25/51)(24/50)

case 2, the first card was not black, but the other two were black, that is, RBB
prob of that = (26/52)(26/51)(25/50)
prob of your event = (26/52)(25/51)(24/50) + (26/52)(26/51)(25/50)
= (26/52)((25/51)(24/50) + (26/51)(25/50)
= (26/52)(25*24 + 26*25)/(50(51))
= ....

Answer 3

Oh, thanks, did not notice that.