P(1) = 12/52
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
P(2) = 12/52 * 11/51
p(3) = 12/52 * 11/51 * 10/50
P(4) = 12/52 * 11/51 * 10/50 * 9/49
The question is asking for the probability of 1, 2, 3 or 4 face cards.
Either-or probabilities are found by adding the individual probabilities.
If three cards are drawn at random from a standard deck of 52 playing cards, what is the probability that at least one of the cards is a face card: that is, one of the cards is a kind, queen, or jack?
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