M C. D. Total
Ma. 3. 6. 2. 11
Fe. 7. 4. 8. 19
Tot. 10. 10. 10. 30
P(Chim or Dog) = P(Chim) + P(Dog) -P(0)
10/30 + 10/30 -0 = 20/30 = 2/3
thirty animals are to be used in a medical experiment on diet deficiency: 3 male and 7 female rhesus monkeys, 6 male and 8 female dogs. If one animal is selected at random, what is the probability of getting a chimpanzee or a dog?
2 answers
eh? No data given on chimps.