Chol

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Questions

The following questions were asked by visitors named Chol.

Alice Dubois was charged $455 in finance charges on a loan for 15 months. Find the finance charge refund if she pays off the loan in full after 10 payments.

Find the annual percentage rate on a loan of $1,500 for 18 months if the loan requires $190 interest and is repaid monthly.

Find the monthly payment. Mortgage amount Annual percentage rate 2. $146,800 5.25% 30 years 4. $113,400 5% 15 years 6. Find the interest paid the mortgage in exercise 2. 8. Find the total interest paid for the mortgage in exercise 4.

Log75+2log2-log3

Answers

The following answers were posted by visitors named Chol.

4x^2 -2x + 11 -40/x+4

P(A) + P(B) - P(A and B) 35/90 + 40/90 -10/90 = 13/18

Total = 55 + 5 + 20 = 80 P( green) + P( yellow) - P(green and yellow) ( 55 + 5)/80 -0 P = 60/80 = .75

x + r = 90 x + r- r = 90 -r x = 90-r

A = 73000(1+ .08/2)^11*2 A = 73000(1.04)^22

78.4-+ 1.96*11/sqrt(36)) (74.81, 81.99)

Given, Age of manoj after 12 years = 3 × Age of Manoj 4 years ago (x + 12 ) = 3 (x – 4) x + 12 = 3x – 12 x -x + 12 = 3x-x -12 12 = 2x -12 12 + 12 = 2x -12 + 12 2x = 24 2x/2 = 24/2 x = 12 Thus, present age of manoj is 12 years.

r = .62(216)^1/3 r = .62(216)^1/3 r = .62*6 = 3.72

(2/25 +13/25) - (2/5 - 14/15) = 15/25 - (-8/15) = 15/25 + 8/15 (45+40)/75 = 85/75 = 17/15

z = (65-76)/6 z = -1.83 z = (90-76)/6 z = 2.33

y = kxz 8 = k(-2)(4) 8 = -8k k = -1 y = -3x 12 = -3x x = -4 Answer is A

y' = -2x*e^(-x^2). At x = 2, that the slope of the tangent line is: y' = (-2)(2)e^[-(2)^2] = -4e^(-4) = -4/e^4. tangent line is: y - 1/e^4 = (-4/e^4)(x - 2) y = (-4/e^4)x + 9/e^4.

1. (2)(3)x^1+3 = 6x^4 2. (4)^3 x^1*3 y^2*3 = 64x^3y^6

f'(x) =e^x -(e^-x))/2

y-intercept of the linear regression is 2.07.

a) unit margin =110-80 = 30 Fixed cost =345000 Break-even = 345000/30 = 11500 units b) new break-even = 345000/40 = 8625 units

a) unit margin = 80-55 =25 break-even = 740000/25 = 29600 units b) (740000+140000)/25 = 880000/25 = 35200

a) Sales =$ 1,800,000 Variable costs = 1,080,000 Contribution margin = $720,000 contribution margin ratio = 720000/1800000 = 40% b) sales = $900,000 contribution margin ratio 32% contribution margin = 288000 less fixed cost = 210000 Income from operation...

Income from operation $78,000

Break-even = 250000/(125-73) = 250000/52 = 4808 units

(300000-30000)/(31-22) = 30000 units

y = -x +2 x^2 + (-x +2)^2 = 34 x ^2 + x^2 -2x -2x +4 = 34 2x^2 -4x + 4 = 34 2x^ -4x + 4 -34 = 34-34 2x^2 -4x - 30 = 0 2(x^2 -2x -15) =0 2(x-5)(x+3) =0 x -5 =0 x =5 x+ 3 = 0 x =-3 y = -3 ,5 (5,-3), (-3,5)

5√3 -7 √2+ 4√3+ 6√2 9√3 - √2

√25*2 = 5√2

-(6x-1)(36x^2 +6x +1)

3(8x^2 + 14x +5) = 3(2x + 1)(4x + 5)

=5√3 - √49*2 + √16*3 + 6√2 =5√3 -7 √2+ 4√3+ 6√2 = 9√3 - √2

=3(8x^2 +14x +5) =3(2x + 1)(4x +5)

mean = (6+15+7+14+11+ 13 + 15 +15)/8 = 12 Median: arranged number from smallest to largest 6 7 11 13 14 15 15 15 Median: (13+14)/2 = 27/2 =13.5 Mode: 15

=(-2)^2 y^1 * (3x^3) = 4(3)y^2 x^3 =12y^2 x^3

= 2x -y +14x^2-7xy +10x = 14x^2 +12x -y -7xy

= x + 2y + 6x^2-12xy+8x = 6x^2 +9x + 2y -12xy

If 3x^y 2. -24x^2+y

-2 = (-2/3)(-6) + b -2 = 4 + b -2-4 = 4-4 +b -6 = b m = -2/3 y = mx + b y = -2x/3 +(-6) y = -2x/3 - 6

f(x) = 3e^x -2x^2 + c 10 = 3e^0 -2(0)^2+ c 10 =3-0+ c 7= c F(x) = 3e^x -2x^2 + 7

Margin units = 32-20 = 12 Fixed cost = 240000 break-even = 240000/12 = 20000 Margin units = 36-20 = 16 Fixed cost = 240000 New break-even = 240000/16 = 15000 20000 units and 15000 units

60000/(105-70) 60000/35 = 1714.29 0r 1714 units

Past year units 6552000/(600-444) = 42000 units Coming year units 655200/ (600-450) = 43680 units

I = prt I = 6510(0.0325)(5)

=24x^6/4x^3- 12^3/4x^3 = 6x^3. -3

Direct labor rate variance (AR-SR)AH (11.6-12)(7500) = $ 3,000 favorable

Let l be 2x -7 w = x A = lw 72 = (2x-7)x 72 = 2x^2 -7x 2x^2 -7x -72 =0 (2x+9)(x-8) = 0 x -8 = 0 x = 8 l = 2x-7 l = 2(8) -7 l = 16-7= 9 L = 9 m and w =8 m

There are 12C3 = 220 ways, group of 3 people from 12 There are 9C3 = 84 ways, none of the three oldest. 220-84 = 136 groups where at least one member is 3 oldest. 136/220 = 0..618

z = (300-300)/(39/sqrt(700)) z = (378-300)/(39/sqrt(700))

Down-hill =20% Cross-country =15% In down-hill and cross-country (20%)(40%) = 0.08

For an inscribed n-gon, circle radius is r A = (r^2 *n sin(2pi/n))/2 For the circumscribed n-gon A = r^2 *n tan(pi/n)

315.10 -239.95 = $75.15

a= x b = x+7 c = 13 x^2 + (x+7)^2 = 13^2 = x^2 + x^2 +7x +7x + 49 = 169 = 2x^2 + 14x + 49 = 169 = 2x^2 + 14x + 49 -169= 169-169 = 2x^2 + 14x -120 = 0 = x^2 +7x -60 = 0 (x -5)(x+12)= 0 x = 5 x = -12 ignored when it is negative a= 5 b = 12

z = (186.3-200)/(30/sqrt(9)) z = -1.37, you can use your table

a. The standard error of the sample mean is 4.564/sqrt(36) = 0.7607 b. yes The mother's mean age student birth lie in interval (28.358, 30.928)

Let Angela needs n flower bulbs for an area measuring 230 square inches. n/230= 1/5 n= 230/5=46 Anglela needs 46 flower bulbs

Three weeks is 7*3= 21 cars In week four is 11* 1 = 11 cars Add/n (21+11)/4 32/4 = 8

2.1(-1.2x+2.3y-1.1) = -2.52x + 4.83y -2.31

M C. D. Total Ma. 3. 6. 2. 11 Fe. 7. 4. 8. 19 Tot. 10. 10. 10. 30 P(Chim or Dog) = P(Chim) + P(Dog) -P(0) 10/30 + 10/30 -0 = 20/30 = 2/3

P(Casper) = .4 P(Denver) = .3 P(Casper u Denver) =0.27 P(Casper|Denver) P(Casper u Denver)/ P(Denver) = .27/.3 = 0.9

Yes there is enough evidence to support---- T = (16-15.6)/(.3/sqrt(8)) df = n-1 df = 8-1 = 7 critical t value = 1.895

FV = 2800e^(.055*12) FV = 2800e^(.66) = 5417.42

(a) R = 15p (b) C = 55 + 4p (c) Revenue [5*15]= $75 Variable cost [5*4]= $20 contribution 55 fixed cost -55 Net profit. 0 (d) 15p = 55 + 4p 11p = 55 p = 5 pizzas break-even Profit = revenue - cost 15(500)-4(500)-55 = $5445 Sell 500 pizzas $5445 (e) profit...