a+10+10/a=72
a^2+10a-72a+10=0
a^2-62a+10=0
solve quadracticly
There are two distinct natural numbers. Each is first increased by 10 then by same percentage as each was increased for the first time. Each number finally results in 72 Find the difference between the numbers.
Please explain easy way
2 answers
How take 10/a can you explain