The work done by an electric force in moving a charge from point A to point B is 3.75 x 10^-3 J. The electric potential difference between the two points is VA - VB = 54.6 V. What is the charge?
Not sure if I did this correctly:
I believe this is an equation:
deltaV= (-Wab)/q
So, 54.6 V= (-3.75 X 10^-3 J)/q
q= -6.868 X 10^-5???
Also, would this be in microcoulombs or coulombs?
1 answer
Your answer is in coulombs and is correct.
1 answer