ΔPE=A= q •Δφ
Δφ= A/q=6.7•10⁻³/1.85•10⁻⁴=36 V
An electric force moves a charge of +1.85 10-4 C from point A to point B and performs 6.70 10-3 J of work on the charge.
(a) What is the difference (EPEA - EPEB) between the electric potential energies of the charge at the two points?
1 answer
1 answer