Ecell = -(0.0592/n)log(dilute soln/concd soln). Substitute to obtain
0.023 = -(0.0592/2)log(x/0.1) and solve for x. You know to let x = dilute soln because the voltage is +.
The voltage generated by the zinc concentration cell described by,
Zn(s)|Zn2 (aq, 0.100 M)||Zn2 (aq, ? M)|Zn(s)
is 23.0 mV at 25 °C. Calculate the concentration of the Zn2 (aq) ion at the cathode.
2 answers
Everything on the above equation is correct besides the log part. its supposed to be log(.1/x), not log(x/.1)...
2 answers