0.027 volts = -(0.05916/2)log(x/0.1)
Solve for x.
The voltage generated by the zinc concentration cell (described by,
Zn(s)|Zn2 (aq, 0.100 M)||Zn2 (aq, ? M)|Zn(s)) is 27.0 mV at 25 °C. Calculate the concentration of the Zn2 (aq) ion at the cathode.
2 answers
10^.91277= x/.1
answer= .818
answer= .818