Sure
one point on your line is point B (-2 , 5)
the other is the midpoint of AC
average x = (-5+3)/2 = -1
average y = (2+4)/2 = 3
so second point is (-1 , 3)
now I bet you know how to find the equation of the line through
(-2 , 5) and (-1 , 3)
The vertices of triangle ABC are A(-5, 2), B(-2, 5), and C(3, 4). Write an equation in slope-intercept form for the line containing the median of triangle ABC through point B.
Can someone please help me figure out how to solve this equation?
3 answers
The median is located in the middle of A to C.
Use your midpoint formula to locate it (remember the midpoint is adding up the ((x1 + x2)/2, (y1 + y2)/2)
So the x co-ordinate of the median is (-5 +3)/2
That is -2/2,
which is 1
(1, y)
You find y.
Then use the B coordinate and your median point (that is 2 points and you find the equation of that line : )
Use your midpoint formula to locate it (remember the midpoint is adding up the ((x1 + x2)/2, (y1 + y2)/2)
So the x co-ordinate of the median is (-5 +3)/2
That is -2/2,
which is 1
(1, y)
You find y.
Then use the B coordinate and your median point (that is 2 points and you find the equation of that line : )
Ms Pi typo, means -2/2 is -1
1 answer