v(t) = dr/dt = <5cost, 3sect tant>
a(t) = dv/dt = <-5sint, 3sect(2sec^2t-1)>
just do normal derivatives of trig functions
the vector function r(t)=< 5 sin t, 3 sec t > , represents the position of a particle at time t. find the velocity v (t) and acceleration a (t).
I don't know how to solve it without the t given. Please help
2 answers
Find the area of the shape shown below.
units2\text{units}^2units
2
u, n, i, t, s, start superscript, 2, end superscript
units2\text{units}^2units
2
u, n, i, t, s, start superscript, 2, end superscript
0 answers