Question
A straight line l is parallel to a vector a and passes through a point B whose position vector is b. The point C has position vector c and vectoe p os the position vector of the foot of the perpendicular drawn from C to l.
Prove that p = [ (c-b)a ]/( | a|^2 )
I don't have a understanding of what's going on here. Could someone please explain??
Prove that p = [ (c-b)a ]/( | a|^2 )
I don't have a understanding of what's going on here. Could someone please explain??