Ask a New Question

Question

Find the position vector of a particle whose acceleration vector is a = (1, 2) with an initial velocity vector (0, 0) and initial position vector (1, 0). (10 points)
Please give explanation and show work. Thank you so much!
4 years ago

Answers

oobleck
a = <1,2>

v = <t+c1,2t+c2>
v(0) = <0,0> so c1=c2=0
v = <t,2t>

r = <1/2 t^2+c1, t^2+c2>
r(0) = <1,0> so c1=1, c2=0
t = <1/2 t^2+1, t^2>
4 years ago
john jones
is that the answer or do we have to plug in numbers from there?
3 years ago

Related Questions

The vector position of a 3.80 g particle moving in the xy plane varies in time according to the foll... The vector position of a 3.75 g particle moving in the xy plane varies in time according to the fol... The vector position of a 3.45 g particle moving in the xy plane varies in time according to 1 = 3... Find the position vector of a particle that has the given acceleration and the specified initial vel... The position vector of m in the same plane are as the point a and b is given by m=1รท2(a+b).if the ve... Find the position vector of a particle whose acceleration vector is a = (6t, 2) with an initial velo... Find the position vector of a particle given a(t)= i + 2 j + 2t k, the initial velocity is zero, and... 13. Given a position vector P=-4i + 6j What is the cosine of the angle between p and (a) the x-axi...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use