Asked by April
Find the position vector of a particle whose acceleration vector is a = (1, 2) with an initial velocity vector (0, 0) and initial position vector (1, 0). (10 points)
Please give explanation and show work. Thank you so much!
Please give explanation and show work. Thank you so much!
Answers
Answered by
oobleck
a = <1,2>
v = <t+c1,2t+c2>
v(0) = <0,0> so c1=c2=0
v = <t,2t>
r = <1/2 t^2+c1, t^2+c2>
r(0) = <1,0> so c1=1, c2=0
t = <1/2 t^2+1, t^2>
v = <t+c1,2t+c2>
v(0) = <0,0> so c1=c2=0
v = <t,2t>
r = <1/2 t^2+c1, t^2+c2>
r(0) = <1,0> so c1=1, c2=0
t = <1/2 t^2+1, t^2>
Answered by
john jones
is that the answer or do we have to plug in numbers from there?
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