The thermal decomposition of potassium chlorate can be used to produce oxygen in the laboratory.
What volume (L) of O2 gas at 25 °C and 1.00 atm pressure is produced by the decomposition of 7.5 g of KClO3 (s)?
Here is my work:
V=nRT/P
.0611995 mol of O2 x .0821Latm/molL x298.15K / 1.0atm=1.498
Why is 1.498 incorrect?
3 answers
.0611995 mol of KClO3 needed to be converted to .09179925 mol of O2 b/c of the coeficients
The answer is correct except for not being labeled and not rounded off correctly.
The thermal decomposition of potassium chlorate can be used to produce oxygen in the laboratory.
2KClO3 (s) ® 2KCl (s) + 3O2 (g)
What volume (L) of O2 gas at 25°C and 1.00 atm pressure is produced by the decomposition of 7.5 g of KClO3 (s)?
Group of answer choices
4.5
3.7
7.5
11
2.2
THE ANSWER IS 2.24 ROUNDED TO 2.2
2KClO3 (s) ® 2KCl (s) + 3O2 (g)
What volume (L) of O2 gas at 25°C and 1.00 atm pressure is produced by the decomposition of 7.5 g of KClO3 (s)?
Group of answer choices
4.5
3.7
7.5
11
2.2
THE ANSWER IS 2.24 ROUNDED TO 2.2
3 answers