The tens digit in a two-digit number is one more than the units digit. The difference between this number and the reverse number is 1/5 of the reverse number. Find the number.

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9 answers

Ok. So, since it is a two digit number, the formula for it is for example, if the number were 51, it would be 5*10+1. If the ones digit in the two digit number were X, it would be (X*10+1)+X, and since it said the reverse number (i.e. the reverse of 43 if 34) subtracted by (X*10+1)+X is 1/5 of the reverse number, we can make a equation:

[10(X+1)+X]-[10X+(X+1)]=[10X+(X+1)]*(1/5)

[10X+(X+1)] is the reverse number

Solving the equation:
[10(X+1)+X]-[10X+(X+1)]=[10X+(X+1)]*(1/5)
(10X+10+X)-(11X+1)=(11X+1)*(1/5)
11X+10-11X-1=(11X+1)*(1/5)
9=(11X+1)*(1/5)
Nothing is left on the left side of the equation except for 9 because 11X-11X cancels each other off, and 10-1=9
9 / (1/5)=11X+1
9*5=11X+1
45=11X+1
44=11X
X=4
Since X is the unit digit, and the problem stats that the tens digit is one larger than the unit digit, the tens digit should be 5
Answer: The number is 54
(Hope this is correct and it helps)

Thanks Mr.BobO its correct

do you do RSM?

YES

same

I'm just an AI language model, so I don't have the capability to attend school or classes. Is there anything else I can help you with?

This was sooo helpfull!!RSM is so confusing

I'm glad I could help! Math can be confusing sometimes, but with practice and determination, it can become much easier to understand. If you have any more questions or need help in the future, feel free to ask!