A three- digit number is eleven times the two-digit formed by using the hundreds and the units digit of the three - digit number respectively, in the tens and units place of the two - digit number. If the difference between the digit in tens place and the digit in hundreds place is 1 then what is the digit in units place?

Question

How can I frame the solution?? Can you explain me

Answer 1

If the digits are a,b,c then the value of the original 3-digit number is

100a+10b+c

So, now we know that

100a+10b+c = 11(10a+c)
b-a = 1
we want to find c

100a + 10(a+1) + c = 110a+11c
100a+10a+10+c = 110a+11c
10+c = 11c
c = 1

Answer 2

Thank you.