Question
a 3 digit, and 1 digit number have a sum of 147, a different of 133 and a product of 980. find the numbers, and then give their quatient.
Answers
drwls
Let A, B and C be the three digits of the three-digit number, in order. Let D be the one-digit number.
100A + 10 B + C + D = 147
100A + 10 B + C - D = 133
2D = 14
D = 7 is the one-digit number
7*(100A + 10 B + C) = 980
(100A + 10 B + C)= 140
That tells you that A = 1, B = 4 and C = 0. The quotient of the numbers is 140/7 = 20
100A + 10 B + C + D = 147
100A + 10 B + C - D = 133
2D = 14
D = 7 is the one-digit number
7*(100A + 10 B + C) = 980
(100A + 10 B + C)= 140
That tells you that A = 1, B = 4 and C = 0. The quotient of the numbers is 140/7 = 20