Asked by emma
in a two digit number, the sum of the digit is 8. the different between this number and the number with the digit reversed is 54, what is the number.
Answers
Answered by
Damon
n m = 10 n + m
n+m = 8
m n = n + 10 m
n + 10 m - (10 n + m) = 54
-9 n + 9 m = 54
-n + m = 6
but
+n + m = 8
---------- add
0 +2m = 14
m = 7
n = 1
so
17
n+m = 8
m n = n + 10 m
n + 10 m - (10 n + m) = 54
-9 n + 9 m = 54
-n + m = 6
but
+n + m = 8
---------- add
0 +2m = 14
m = 7
n = 1
so
17
Answered by
Reiny
original:
unit digit -- x
tens digit -- 8-x
the number: 10(8-x) + x
the number reversed: 10x + (8-x)
10x + 8-x - (10(8-x) + x) = 54
10x + 8 -x - 80 + 10x - x = 54
18x = 126
x = 7
unit digit = 7
tens digit = 1
original number 17
number reversed 71
or
original number is 71
number reversed is 17
in both cases the difference between them is 54
unit digit -- x
tens digit -- 8-x
the number: 10(8-x) + x
the number reversed: 10x + (8-x)
10x + 8-x - (10(8-x) + x) = 54
10x + 8 -x - 80 + 10x - x = 54
18x = 126
x = 7
unit digit = 7
tens digit = 1
original number 17
number reversed 71
or
original number is 71
number reversed is 17
in both cases the difference between them is 54
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