What is the linear equation that will represent the second statement in the following problem:
"The sum of the digits of a three-digit number is 12. If the hundreds digit is replaced by the tens digit, the tens digit by the units digit, and the units digit by the hundreds digit, the new number is greater than the original number by 108. If the tens and the hundreds digits are interchanged, the original number is 90 less than the number formed. Find the original number."
3 answers
100t+10u+h = 100h+10t+u + 108
Four digit number. Greater than 4000. Sum of its hundreds digit and it's ones digit is 9. Twice it's tens digit is 2 more than its thousands digit. Sum of one- fifth of its hundreds digit and two-thirds of its ones digit is 6. It's 10 digit is 1 less than its thousands digit.
a + b + c = 12
100b + 10c + a - ( 100a + 10b + c ) = 108
100b + 10a + c - ( 100a + 10b + a ) = 90
100b + 10c + a - ( 100a + 10b + c ) = 108
100b + 10a + c - ( 100a + 10b + a ) = 90
1 answer