a^2+ (a+1)^2=365
a^2 + a^2+2a+1=365
2a^2+2a-364=0
a^2+a-182=0
now apply the quadratic equation to find the a, the lower number. In my head, I get somehing in the lower teens
the sum of the squares of two consecutive integers is 365. find the integers using the quadratic formula.
if possible, show your steps! :)
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