THE SUM OF THE 2ND AND 5TH TERMS OF AN A.P IS 42.

Question

IF THE DIFFERENCE BETWEEN THE 6TH AND 3RD TERM IS 12,
FIND THE:
COMMON DIFFERENCE,
1ST TERM,
20TH TERM.

Answer 1

Let
d = the common difference
t(n)=nth term

t(6)-t(5)=d
t(5)-t(4)=d
t(4)-t(3)=d
Add
t(6)-t(3)=3d
or
3d=12
Solve for the common difference d=4

Sum of the 2nd and 5th terms = 42
t(2)+t(5)
=t(2)+(t(2)+3d)
=2*t(2)+12 = 42
Solve for t(2) = 15

t(1) should be t(2)-1=15-4=11
and
t(20)=t(1)+19d

Answer 2

Explain in a simpler way please

Answer 3

I didn't understand

Answer 4

Illustrate

Answer 5

I don't understand

Answer 6

After the step where you expande t5 i just got lost

Answer 7

Understood
Thanks alot

Answer 8

Please break it down to ss1 level of understanding

Answer 9

please break it down into a more simple form.